Updated August 5, 2020 |
Infoplease Staff
Table of contents
The following table shows ten cities in the United States with a population of 100,000 people or more with the highest percentage of same-sex partners.
| Same-sex partners | Percent of all households |
|---|---|
| San Francisco-Oakland-Fremont, Calif. | 1.36% |
| Burlington-South Burlington, Vt. | 1.12 |
| Barnstable Town, Mass. | 1.10 |
| Portland-South Portland-Biddeford, Maine | 1.09 |
| Santa Rosa-Petaluma, Calif. | 1.03 |
| Portland-Vancouver-Beaverton, Ore.-Wash. | 1.00 |
| Santa Cruz-Watsonville, Calif. | 0.95 |
| Springfield, Mass. | 0.92 |
| Seattle-Tacoma-Bellevue, Wash. | 0.91 |
| Boston-Cambridge-Quincy, Mass. | 0.91 |
Source: U.S. Census Bureau, American Community Survey 2005-9
| Unmarried-Partner Households by Sex of Partners and Race and Hispanic Origin of Householder, 2000 | Marital Status | Divorce Rates by State, 1990–2004 |
